Design Circular Deque
设计循环双端队列
题目描述
设计实现双端队列,需要支持以下操作:
MyCircularDeque(k)
:构造函数,双端队列的大小为k。insertFront()
:将一个元素添加到双端队列头部。 如果操作成功返回 true。insertLast()
:将一个元素添加到双端队列尾部。如果操作成功返回 true。deleteFront()
:从双端队列头部删除一个元素。 如果操作成功返回 true。deleteLast()
:从双端队列尾部删除一个元素。如果操作成功返回 true。getFront()
:从双端队列头部获得一个元素。如果双端队列为空,返回 -1。getRear()
:获得双端队列的最后一个元素。 如果双端队列为空,返回 -1。isEmpty()
:检查双端队列是否为空。isFull()
:检查双端队列是否满了。
示例:
MyCircularDeque circularDeque = new MycircularDeque(3); // 设置容量大小为3
circularDeque.insertLast(1); // 返回 true
circularDeque.insertLast(2); // 返回 true
circularDeque.insertFront(3); // 返回 true
circularDeque.insertFront(4); // 已经满了,返回 false
circularDeque.getRear(); // 返回 2
circularDeque.isFull(); // 返回 true
circularDeque.deleteLast(); // 返回 true
circularDeque.insertFront(4); // 返回 true
circularDeque.getFront(); // 返回 4
解法
解法一:数组实现
时间复杂度:
O(1)
空间复杂度:
O(1)
type MyCircularDeque struct {
nums []int
counts int
}
/** Initialize your data structure here. Set the size of the deque to be k. */
func Constructor(k int) MyCircularDeque {
return MyCircularDeque{
nums: []int{},
counts: k,
}
}
/** Adds an item at the front of Deque. Return true if the operation is successful. */
func (this *MyCircularDeque) InsertFront(value int) bool {
if len(this.nums) >= this.counts {
return false
}
this.nums = append([]int{value}, this.nums...)
return true
}
/** Adds an item at the rear of Deque. Return true if the operation is successful. */
func (this *MyCircularDeque) InsertLast(value int) bool {
if len(this.nums) >= this.counts {
return false
}
this.nums = append(this.nums, value)
return true
}
/** Deletes an item from the front of Deque. Return true if the operation is successful. */
func (this *MyCircularDeque) DeleteFront() bool {
if len(this.nums) <= 0 {
return false
}
this.nums = this.nums[1:]
return true
}
/** Deletes an item from the rear of Deque. Return true if the operation is successful. */
func (this *MyCircularDeque) DeleteLast() bool {
if len(this.nums) <= 0 {
return false
}
this.nums = this.nums[:len(this.nums)-1]
return true
}
/** Get the front item from the deque. */
func (this *MyCircularDeque) GetFront() int {
if len(this.nums) <= 0 {
return -1
}
num := this.nums[0]
return num
}
/** Get the last item from the deque. */
func (this *MyCircularDeque) GetRear() int {
if len(this.nums) <= 0 {
return -1
}
num := this.nums[len(this.nums)-1]
return num
}
/** Checks whether the circular deque is empty or not. */
func (this *MyCircularDeque) IsEmpty() bool {
return len(this.nums) <= 0
}
/** Checks whether the circular deque is full or not. */
func (this *MyCircularDeque) IsFull() bool {
return len(this.nums) >= this.counts
}
解法二:链表实现
代码略
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